Number.IntegerDivide
Divides two numbers and returns the integer portion of the result.
function (optionalnumber1as nullable any, optionalnumber2as nullable any, optionalprecisionas nullable any) as nullable any
Returns the integer portion of the result from dividing a number,
number1, by another number, number2. If number1 or number2 are null, Number.IntegerDivide returns null. Number.Operations
Divide 6 by 4.
Number.IntegerDivide(6, 4)
1
Divide 8.3 by 3.
Number.IntegerDivide(8.3, 3)
2
Last modified 4yr ago