Number.IntegerDivide
Divides two numbers and returns the integer portion of the result.
function (optionalnumber1
as nullable any, optionalnumber2
as nullable any, optionalprecision
as nullable any) as nullable any
Returns the integer portion of the result from dividing a number,
number1
, by another number, number2
. If number1
or number2
are null, Number.IntegerDivide
returns null. Number.Operations
Divide 6 by 4.
Number.IntegerDivide(6, 4)
1
Divide 8.3 by 3.
Number.IntegerDivide(8.3, 3)
2
Last modified 4yr ago