Number.Mod
Integer divides two numbers and returns the remainder.
function (optionalnumber
as nullable any, optionaldivisor
as nullable any, optionalprecision
as nullable any) as nullable any
Returns the remainder resulting from the integer division of
number
by divisor
. If number
or divisor
are null, Number.Mod
returns null. Number.Operations
Find the remainder when you divide 5 by 3.
Number.Mod(5, 3)
2
Last modified 4yr ago