Number.Mod
Integer divides two numbers and returns the remainder.
function (optionalnumberas nullable any, optionaldivisoras nullable any, optionalprecisionas nullable any) as nullable any
Returns the remainder resulting from the integer division of
number by divisor. If number or divisor are null, Number.Mod returns null. Number.Operations
Find the remainder when you divide 5 by 3.
Number.Mod(5, 3)
2
Last modified 4yr ago